The Quantised Oscillator can be assumed ot be an Oscillation Spring Block System about its mean position. The energy of the oscillator is E= 1/2 KA2 and the frequency of the oscillator is f=1/2∏√K/m.
The interatomic \"spring\" (chemical bond) between atoms in a block of aluminum to be 16 N/m. Since in our model each atom is connected to two springs, each half the length of the interatomic bond, the effective \"interatomic spring stiffness\" for an oscillator is 4*16 N/m = 64 N/m. The mass of one mole of aluminum is 27 grams (0.027 kilograms). What is the energy, in joules, of one quantum of energy for an atomic oscillator in a block of aluminum?
Attached file(s)
Solution Attachment
Solution document is in Word format
Original Price: $5.99 Now at: $2.99
Comments (0)
Comments
No comments found
The Quantised Oscillator can be assum | Solution Library Search